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Selected Layer/Datatype wrong from seletec_layer ...
I'm not able to get the layer and datatype correct out of my layout.
The values do not match the current situation, some are correct other wrong.
from pya import *
lv = pya.Application.instance().main_window().current_view()
layout = lv.active_cellview().layout()
sel_layers=[]
sel_layers = lv.selected_layers()
if len(sel_layers) == 0:
print("No Layer selected")
for l in sel_layers:
a = l.current()
li = a.layer_index()
myLayer = layout.layer(li,0)
info = layout.get_info(myLayer)
print(info.name, info.layer, info.datatype)
BR,
Andy
The values do not match the current situation, some are correct other wrong.
from pya import *
lv = pya.Application.instance().main_window().current_view()
layout = lv.active_cellview().layout()
sel_layers=[]
sel_layers = lv.selected_layers()
if len(sel_layers) == 0:
print("No Layer selected")
for l in sel_layers:
a = l.current()
li = a.layer_index()
myLayer = layout.layer(li,0)
info = layout.get_info(myLayer)
print(info.name, info.layer, info.datatype)
BR,
Andy
Comments
Hi Andy,
This should be sufficient:
BTW: This Forum supports Markdown. So you can format source code using four spaces as indent. For Python this is mandatory - otherwise I can only guess the code structure.
Matthias